AP CHEMISTRY Unit Guides
UNIT 1. Atomic Structure and Properties
UNIT 2 Compound Structure and Properties
Guiding question |
How does the periodic table help us to predict patterns and trends in the properties of the elements? |
Learning outcomes
After studying this topic students should be able to:
Understand | Apply their knowledge to |
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AHL | AHL |
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Guiding Question |
How does the classification of organic molecules help you to predict their properties? |
Learning Outcomes
After studying this topic you should be able to:
Understand | Apply your knowledge to |
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AHL | AHL |
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LEARNING OBJECTIVE 2.3.A Represent an ionic solid with a particulate model that is consistent with Coulomb’s law and the properties of the constituent ions. |
ESSENTIAL KNOWLEDGE 2.3.A.1 The cations and anions in an ionic crystal are arranged in a systematic, periodic 3-D array that maximizes the attractive forces among cations and anions while minimizing the repulsive forces. Exclusion Statement: Knowledge of specific crystal structures is not essential to an understanding of the learning objective and will not be assessed on the AP Exam. |
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LEARNING OBJECTIVE 2.4.A Represent a metallic solid and/or alloy using a model to show essential characteristics of the structure and interactions present in the substance. |
ESSENTIAL KNOWLEDGE 2.4.A.1 Metallic bonding can be represented as an array of positive metal ions surrounded by delocalized valence electrons (i.e., a “sea of electrons”). 2.4.A.2 Interstitial alloys form between atoms of significantly different radii, where the smaller atoms fill the interstitial spaces between the larger atoms (e.g., with steel in which carbon occupies the interstices in iron). 2.4.A.3 Substitutional alloys form between atoms of comparable radius, where one atom substitutes for the other in the lattice (e.g., in certain brass alloys, other elements, usually zinc, substitute for copper). |
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LEARNING OBJECTIVE 2.5.ARepresent a molecule with a Lewis diagram. |
ESSENTIAL KNOWLEDGE 2.5.A.1 Lewis diagrams can be constructed according to an established set of principles. |
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LEARNING OBJECTIVE 2.6.A Represent a molecule with a Lewis diagram that accounts for resonance between equivalent structures or that uses formal charge to select between nonequivalent structures. |
ESSENTIAL KNOWLEDGE 2.6.A.1 In cases where more than one equivalent Lewis structure can be constructed, resonance must be included as a refinement to the Lewis structure. In many such cases, this refinement is needed to provide qualitatively accurate predictions of molecular structure and properties. 2.6.A.2 The octet rule and formal charge can be used as criteria for determining which of several possible valid Lewis diagrams provides the best model for predicting molecular structure and properties. 2.6.A.3 As with any model, there are limitations to the use of the Lewis structure model, particularly in cases with an odd number of valence electrons. |
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LEARNING OBJECTIVE 2.7.A Based on the relationship between Lewis diagrams, VSEPR theory, bond orders, and bond polarities:VSEPR theory uses the Coulombic repulsion between electrons as a basis for predicting the arrangement of electron pairs around a central atom. i. Explain structural properties of molecules. ii. Explain electron properties of molecules. |
ESSENTIAL KNOWLEDGE 2.7.A.1 VSEPR theory uses Coulombic repulsion between electron pairs around a central atom to predict: i. Structural properties of molecules. ii. Electron properties of molecules. 2.7.A.2 Both Lewis diagrams and VSEPR theory must be used for predicting electronic and structural properties of many covalently bonded molecules and polyatomic ions, including: i. Molecular geometry (linear, trigonal planar, tetrahedral, trigonal pyramidal, bent, trigonal bipyramidal, seesaw, T-shaped, octahedral, square pyramidal, square planar) ii. Bond angles iii. Relative bond energies based on bond order iv. Relative bond lengths (multiple bonds, effects of atomic radius) v. Presence of a dipole moment vi. Hybridization of valence orbitals for atoms within a molecule or polyatomic ion. 2.7.A.3 The terms “hybridization” and “hybrid atomic orbital” describe the arrangement of electrons around a central atom:- sp hybridized atoms have ideal bond angles of 180°- sp² hybridized atoms have ideal bond angles of 120°- sp³ hybridized atoms have ideal bond angles of 109.5° Exclusion Statements: -Understanding of the derivation and depiction of hybrid orbitals will not be assessed on the AP Exam. The course includes the distinction between sigma and pi bonding, the use of VSEPR to explain molecular shapes, and the sp, sp², and sp³ nomenclature. – Hybridization involving d orbitals will not be assessed on the AP Exam. – When an atom has more than four pairs of electrons surrounding the central atom, students are only responsible for the shape of the resulting molecule. 2.7.A.4 Bond formation is associated with overlap between atomic orbitals. In multiple bonds, such overlap leads to the formation of both sigma and pi bonds. The overlap is stronger in sigma than pi bonds, which is reflected in sigma bonds having greater bond energy than pi bonds. The presence of a pi bond also prevents rotation of the bond and leads to geometric isomers. Exclusion Statement: Molecular orbital theory is recommended for deeper bonding insight but will not be explicitly assessed on the AP Exam, including molecular orbital diagrams, filling, or distinctions between bonding, nonbonding, and antibonding orbitals. |
UNIT 3 Properties of Substances and Mixtures
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LEARNING OBJECTIVE 3.1.A Explain the relationship between the chemical structures of molecules and the relative strength of their intermolecular forces when:i. The molecules are of the same chemical species.ii. The molecules are of two different chemical species. |
ESSENTIAL KNOWLEDGE 3.1.A.1 London dispersion forces are a result of the Coulombic interactions between temporary, fluctuating dipoles. London dispersion forces are often the strongest net intermolecular force between large molecules. i. Dispersion forces increase with increasing contact area between molecules and with increasing polarizability of the molecules. ii. The polarizability of a molecule increases with an increasing number of electrons in the molecule and the size of the electron cloud. It is enhanced by the presence of pi bonding. iii. The term “London Dispersion Forces” should not be used synonymously with the term “van der Waals forces.” 3.1.A.2 The dipole moment of a polar molecule leads to additional interactions with other chemical species. i. Dipole-induced dipole interactions are present between a polar and nonpolar molecule. These forces are always attractive. The strength of these forces increases with the magnitude of the dipole of the polar molecule and with the polarizability of the nonpolar molecule. ii. Dipole-dipole interactions are present between polar molecules. The interaction strength depends on the magnitudes of the dipoles and their relative orientation. Interactions between polar molecules are typically greater than those between nonpolar molecules of comparable size because these interactions act in addition to London dispersion forces. iii. Ion-dipole forces of attraction are present between ions and polar molecules. These tend to be stronger than dipole-dipole forces. 3.1.A.3 The relative strength and orientation dependence of dipole-dipole and ion-dipole forces can be understood qualitatively by considering the sign of the partial charges responsible for the molecular dipole moment, and how these partial charges interact with an ion or with an adjacent dipole. 3.1.A.4 Hydrogen bonding is a strong type of intermolecular interaction that exists when hydrogen atoms covalently bonded to the highly electronegative atoms (N, O, and F) are attracted to the negative end of a dipole formed by the electronegative atom (N, O, and F) in a different molecule, or a different part of the same molecule. 3.1.A.5 In large biomolecules, noncovalent interactions may occur between different molecules or between different regions of the same large biomolecule. |
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| LEARNING OBJECTIVE |
| 3.2.A Explain the relationship among the macroscopic properties of a substance, the particulate-level structure of the substance, and the interactions between these particles. |
| ESSENTIAL KNOWLEDGE |
3.2.A.1 Many properties of liquids and solids are determined by the strengths and types of intermolecular forces present. Because intermolecular interactions are overcome completely when a substance vaporizes, the vapor pressure and boiling point are directly related to the strength of those interactions. Melting points also tend to correlate with interaction strength, but because the interactions are only rearranged in melting, the relations can be more subtle. 3.2.A.2 Particulate-level representations, showing multiple interacting chemical species, are a useful means to communicate or understand how intermolecular interactions help to establish macroscopic properties. 3.2.A.3 Due to strong interactions between ions, ionic solids tend to have low vapor pressures, high melting points, and high boiling points. They tend to be brittle due to the repulsion of like charges caused when one layer slides across another layer. They conduct electricity only when the ions are mobile, as when the ionic solid is melted (i.e., in a molten state) or dissolved in water or another solvent. 3.2.A.4 In covalent network solids, the atoms are covalently bonded together into a three-dimensional network (e.g., diamond) or layers of two-dimensional networks (e.g., graphite). These are only formed from nonmetals and metalloids: elemental (e.g., diamond, graphite) or binary compounds (e.g., silicon dioxide and silicon carbide). Due to the strong covalent interactions, covalent solids have high melting points. Three-dimensional network solids are also rigid and hard because the covalent bond angles are fixed. However, graphite is soft because adjacent layers can slide past each other relatively easily. 3.2.A.5 Molecular solids are composed of distinct, individual units of covalently bonded molecules attracted to each other through relatively weak intermolecular forces. Molecular solids generally have a low melting point because of the relatively weak intermolecular forces present between the molecules. They do not conduct electricity because their valence electrons are tightly held within the covalent bonds and the lone pairs of each constituent molecule. Molecular solids are sometimes composed of very large molecules or polymers. 3.2.A.6 Metallic solids are good conductors of electricity and heat, due to the presence of free valence electrons. They also tend to be malleable and ductile, due to the ease with which the metal cores can rearrange their structure. In an interstitial alloy, interstitial atoms tend to make the lattice more rigid, decreasing malleability and ductility. Alloys typically retain a sea of mobile electrons and so remain conducting. 3.2.A.7 In large biomolecules or polymers, noncovalent interactions may occur between different molecules or between different regions of the same large biomolecule. The functionality and properties of such molecules depend strongly on the shape of the molecule, which is largely dictated by noncovalent interactions. | |
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| LEARNING OBJECTIVE |
| 3.3.A |
| Represent the differences between solid, liquid, and gas phases using a particulate-level model. |
| ESSENTIAL KNOWLEDGE |
| 3.3.A.1 |
| Solids can be crystalline, where the particles are arranged in a regular three-dimensional structure, or they can be amorphous, where the particles do not have a regular, orderly arrangement. In both cases, the motion of the individual particles is limited, and the particles do not undergo overall translation with respect to each other. The structure of the solid is influenced by interparticle interactions and the ability of the particles to pack together. |
| 3.3.A.2 |
| The constituent particles in liquids are in close contact with each other, and they are continually moving and colliding. The arrangement and movement of particles are influenced by the nature and strength of the forces (e.g., polarity, hydrogen bonding, and temperature) between the particles. |
| 3.3.A.3 |
| The solid and liquid phases for a particular substance typically have similar molar volume because, in both phases, the constituent particles are in close contact at all times. |
| 3.3.A.4 |
| In the gas phase, the particles are in constant motion. Their frequencies of collision and the average spacing between them are dependent on temperature, pressure, and volume. Because of this constant motion, and minimal effects of forces between particles, a gas has neither a definite volume nor a definite shape. |
| Exclusion Statement: Understanding/interpreting phase diagrams will not be assessed on the AP Exam. |
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| LEARNING OBJECTIVE |
| 3.4.A Explain the relationship between the macroscopic properties of a sample of gas or mixture of gases using the ideal gas law. |
| ESSENTIAL KNOWLEDGE |
3.4.A.1 The macroscopic properties of ideal gases are related through the ideal gas law: EQN: PV = nRT. |
3.4.A.2 In a sample containing a mixture of ideal gases, the pressure exerted by each component (the partial pressure) is independent of the other components. Therefore, the partial pressure of a gas within the mixture is proportional to its mole fraction (X), and the total pressure of the sample is the sum of the partial pressures. EQN: Pₐ = Pₜₒₜₐₗ × Xₐ, where Xₐ = moles A / total moles; EQN: Pₜₒₜₐₗ = Pₐ + Pᵦ + P𝒸 + … |
| 3.4.A.3 Graphical representations of the relationships between P, V, T, and n are useful to describe gas behavior. |
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| LEARNING OBJECTIVE |
| 3.5.A Explain the relationship between the motion of particles and the macroscopic properties of gases with: |
| i. The kinetic molecular theory (KMT). |
| ii. A particulate model. |
| iii. A graphical representation. |
| ESSENTIAL KNOWLEDGE |
| 3.5.A.1 The kinetic molecular theory (KMT) relates the macroscopic properties of gases to motions of the particles in the gas. The Maxwell-Boltzmann distribution describes the distribution of the kinetic energies of particles at a given temperature. |
| 3.5.A.2 All the particles in a sample of matter are in continuous, random motion. The average kinetic energy of a particle is related to its average velocity by the equation: |
| KE = ½ mv² |
| 3.5.A.3 The Kelvin temperature of a sample of matter is proportional to the average kinetic energy of the particles in the sample. |
| 3.5.A.4 The Maxwell-Boltzmann distribution provides a graphical representation of the energies/velocities of particles at a given temperature. |
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| LEARNING OBJECTIVE |
| 3.6.A Explain the relationship among non-ideal behaviors of gases, interparticle forces, and/or volumes. |
| ESSENTIAL KNOWLEDGE |
| 3.6.A.1 The ideal gas law does not explain the actual behavior of real gases. Deviations from the ideal gas law may result from interparticle attractions among gas molecules, particularly at conditions that are close to those resulting in condensation. Deviations may also arise from particle volumes, particularly at extremely high pressures. |
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| LEARNING OBJECTIVE |
| 3.7.A Calculate the number of solute particles, volume, or molarity of solutions. |
| ESSENTIAL KNOWLEDGE |
| 3.7.A.1 Solutions, also sometimes called homogeneous mixtures, can be solids, liquids, or gases. In a solution, the macroscopic properties do not vary throughout the sample. In a heterogeneous mixture, the macroscopic properties depend on location in the mixture. |
| 3.7.A.2 Solution composition can be expressed in a variety of ways; molarity is the most common method used in the laboratory. |
| Equation: M = nₛₒₗᵤₜₑ / Lₛₒₗᵤₜᵢₒₙ |
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| LEARNING OBJECTIVE |
3.8.A Using particulate models for mixtures: i. Represent interactions between components. ii. Represent concentrations of components. |
| ESSENTIAL KNOWLEDGE |
| 3.8.A.1 Particulate representations of solutions communicate the structure and properties of solutions, by illustration of the relative concentrations of the components in the solution and/or drawings that show interactions among the components. |
| Exclusion Statement: Colligative properties will not be assessed on the AP Exam. |
| Exclusion Statement: Calculations of molality, percent by mass, and percent by volume for solutions will not be assessed on the AP Exam. |
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| LEARNING OBJECTIVE |
| 3.10.A Explain the relationship between the solubility of ionic and molecular compounds in aqueous and nonaqueous solvents, and the intermolecular interactions between particles. |
| ESSENTIAL KNOWLEDGE |
| 3.10.A.1 Substances with similar intermolecular interactions tend to be miscible or soluble in one another. |
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| LEARNING OBJECTIVE |
| 3.11.A Explain the relationship between a region of the electromagnetic spectrum and the types of molecular or electronic transitions associated with that region. |
| ESSENTIAL KNOWLEDGE |
| 3.11.A.1 Differences in absorption or emission of photons in different spectral regions are related to the different types of molecular motion or electronic transition: |
| i. Microwave radiation is associated with transitions in molecular rotational levels. |
| ii. Infrared radiation is associated with transitions in molecular vibrational levels. |
| iii. Ultraviolet/visible radiation is associated with transitions in electronic energy levels. |
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| LEARNING OBJECTIVE |
| 3.12.A Explain the properties of an absorbed or emitted photon in relationship to an electronic transition in an atom or molecule. |
| ESSENTIAL KNOWLEDGE |
| 3.12.A.1 When a photon is absorbed (or emitted) by an atom or molecule, the energy of the species is increased (or decreased) by an amount equal to the energy of the photon. |
| 3.12.A.2 The wavelength of the electromagnetic wave is related to its frequency and the speed of light by the equation: |
| EQN: c = λν. |
| The energy of a photon is related to the frequency of the electromagnetic wave through Planck’s equation: |
| EQN: E = hν. |
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LEARNING OBJECTIVE 3.13.A Explain the amount of light absorbed by a solution of molecules or ions in relationship to the concentration, path length, and molar absorptivity. |
ESSENTIAL KNOWLEDGE 3.13.A.1 The Beer-Lambert law relates the absorption of light by a solution to three variables according to the equation: The molar absorptivity, ε, describes how intensely a chemical species absorbs light of a specific wavelength. The path length, b, and concentration, c, are proportional to the number of light-absorbing particles in the light path. 3.13.A.2 In most experiments the path length and wavelength of light are held constant. In such cases, the absorbance is proportional only to the concentration of absorbing molecules or ions. The spectrophotometer is typically set to the wavelength of maximum absorbance (optimum wavelength) for the species being analyzed to ensure the maximum sensitivity of measurement. |
UNIT 4 Chemical Reactions
Guiding Question |
What can be deduced from the temperature change that accompanies chemical or physical change? |
Learning outcomes.
After studying this topic students should be able to:
Understand | Apply their knowledge to |
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IB Clarification Notes | |
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Guiding Question |
How does application of the law of conservation of energy help us to predict energy changes during reactions? |
Learning outcomes.
After studying this topic students should be able to:
Understand | Apply their knowledge to |
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AHL | AHL |
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ΔH⦵ = Σ ΔHf⦵products − Σ ΔHf⦵reactants
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IB Clarification Notes | |
ΔH⦵ = Σ ΔHf⦵products − Σ ΔHf ⦵reactants
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Guiding question |
What are the challenges of using chemical energy to address our energy needs? |
Learning outcomes
After studying this topic students should be able to:
Understand | Apply their knowledge to |
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IB Clarification Notes | |
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Guiding Question |
What determines the direction of chemical change? |
Learning outcomes
After studying this topic students should be able to:
Understand | Apply their knowledge to |
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IB Clarification Notes | |
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LEARNING OBJECTIVE 4.5.A Explain changes in the amounts of reactants and products based on the balanced reaction equation for a chemical process. |
ESSENTIAL KNOWLEDGE |
4.5.A.1 Because atoms must be conserved during a chemical process, it is possible to calculate product amounts by using known reactant amounts, or to calculate reactant amounts given known product amounts. 4.5.A.2 Coefficients of balanced chemical equations contain information regarding the proportionality of the amounts of substances involved in the reaction. These values can be used in chemical calculations involving the mole concept. 4.5.A.3 Stoichiometric calculations can be combined with the ideal gas law and calculations involving molarity to quantitatively study gases and solutions. |
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| LEARNING OBJECTIVE |
| 4.6.A |
| Identify the equivalence point in a titration based on the amounts of the titrant and analyte, assuming the titration reaction goes to completion. |
| ESSENTIAL KNOWLEDGE |
| 4.6.A.1 |
| Titrations may be used to determine the amount of an analyte in solution. The titrant has a known concentration of a species that reacts specifically and quantitatively with the analyte. The equivalence point of the titration occurs when the analyte is totally consumed by the reacting species in the titrant. The equivalence point is often indicated by a change in a property (such as color) that occurs when the equivalence point is reached. This observable event is called the endpoint of the titration. |
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| LEARNING OBJECTIVE |
| 4.7.A |
| Identify a reaction as acid-base, oxidation-reduction, or precipitation. |
| ESSENTIAL KNOWLEDGE |
| 4.7.A.1 |
| Acid-base reactions involve transfer of one or more protons (H⁺ ions) between chemical species. |
| 4.7.A.2 |
| Oxidation-reduction (redox) reactions involve transfer of one or more electrons between chemical species, as indicated by changes in oxidation numbers of the involved species. Combustion is an important subclass of oxidation-reduction reactions, in which a species reacts with oxygen gas. In the case of hydrocarbons, carbon dioxide and water are products of complete combustion. |
| 4.7.A.3 |
| In a redox reaction, electrons are transferred from the species that is oxidized to the species that is reduced. |
| Exclusion Statement: The meaning of the terms “reducing agent” and “oxidizing agent” will not be assessed on the AP Exam. |
| 4.7.A.4 |
| Oxidation numbers may be assigned to each of the atoms in the reactants and products; this is often an effective way to identify the oxidized and reduced species in a redox reaction. |
| 4.7.A.5 |
| Precipitation reactions frequently involve mixing ions in aqueous solution to produce an insoluble or sparingly soluble ionic compound. All sodium, potassium, ammonium, and nitrate salts are soluble in water. |
| Exclusion Statement: Rote memorization of “solubility rules” other than those implied in 4.7.A.5 will not be assessed on the AP Exam. |
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| LEARNING OBJECTIVE |
| 4.8.A |
| Identify species as Brønsted-Lowry acids, bases, and/or conjugate acid-base pairs, based on proton-transfer involving those species. |
| ESSENTIAL KNOWLEDGE |
| 4.8.A.1 |
| Identify species as Brønsted-Lowry acids, bases, and/or conjugate acid-base pairs, based on proton-transfer involving those species. By definition, a Brønsted-Lowry acid is a proton donor and a Brønsted-Lowry base is a proton acceptor. |
| 4.8.A.2 |
| Only in aqueous solutions, water plays an important role in many acid-base reactions, as its molecular structure allows it to accept protons from and donate protons to dissolved species. |
| 4.8.A.3 |
| When an acid or base ionizes in water, the conjugate acid-base pairs can be identified and their relative strengths compared. |
| Exclusion Statement: Lewis acid-base concepts will not be assessed on the AP Exam. The emphasis in AP Chemistry is on reactions in aqueous solution. |
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| LEARNING OBJECTIVE |
| 4.9.A |
| Represent a balanced redox reaction equation using half-reactions. |
| ESSENTIAL KNOWLEDGE |
| 4.9.A.1 |
| Balanced chemical equations for redox reactions can be constructed from half-reactions. |
UNIT 5 Kinetics
Guiding Question |
How are chemical equations used to calculate reacting ratios? |
Learning outcomes
After studying this topic students should be able to:
Understand | Apply their knowledge to |
→ The masses and/or volumes of reactants and products. → The concentrations of reactants and products for reactions occurring in solution.
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IB Clarification Notes | |
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Guiding question |
How can the rate of a reaction be controlled? |
Learning outcomes
After studying this topic students should be able to:
Understand | Apply their knowledge to |
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AHL | AHL |
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IB Clarification notes | |
AHL
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Guiding question |
How can the extent of a reversible reaction be influenced? |
Learning outcomes
After studying this topic students should be able to:
Understand | Apply their knowledge to |
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AHL | AHL |
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IB Clarification Notes | |
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| Required Course Content |
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| LEARNING OBJECTIVE |
| 5.4.A Represent an elementary reaction as a rate law expression using stoichiometry. |
| ESSENTIAL KNOWLEDGE |
| 5.4.A.1 The rate law of an elementary reaction can be inferred from the stoichiometry of the particles participating in a collision. |
| 5.4.A.2 Elementary reactions involving the simultaneous collision of three or more particles are rare. |
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| LEARNING OBJECTIVE |
| 5.5.A Explain the relationship between the rate of an elementary reaction and the frequency, energy, and orientation of particle collisions. |
| ESSENTIAL KNOWLEDGE |
| 5.5.A.1 For an elementary reaction to successfully produce products, reactants must successfully collide to initiate bond-breaking and bond-making events. |
| 5.5.A.2 In most reactions, only a small fraction of the collisions leads to a reaction. Successful collisions have both sufficient energy to overcome the activation energy requirements and orientations that allow the bonds to rearrange in the required manner. |
| 5.5.A.3 The Maxwell-Boltzmann distribution curve describes the distribution of particle energies; this distribution can be used to gain a qualitative estimate of the fraction of collisions with sufficient energy to lead to a reaction, and also how that fraction depends on temperature. |
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| LEARNING OBJECTIVE |
| 5.6.A Represent the activation energy and overall energy change in an elementary reaction using a reaction energy profile. |
| ESSENTIAL KNOWLEDGE |
| 5.6.A.1 Elementary reactions typically involve the breaking of some bonds and the forming of new ones. |
| 5.6.A.2 The reaction coordinate is the axis along which the complex set of motions involved in rearranging reactants to form products can be plotted. |
| 5.6.A.3 The energy profile gives the energy along the reaction coordinate, which typically proceeds from reactants, through a transition state, to products. The energy difference between the reactants and the transition state is the activation energy for the forward reaction. |
| 5.6.A.4 The rate of an elementary reaction is temperature dependent because the proportion of particle collisions that are energetic enough to reach the transition state varies with temperature. The Arrhenius equation relates the temperature dependence of the rate of an elementary reaction to the activation energy needed by molecular collisions to reach the transition state. |
| Exclusion Statement: Calculations involving the Arrhenius equation will not be assessed on the AP Exam. |
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| LEARNING OBJECTIVE |
| 5.7.A Identify the components of a reaction mechanism. |
| ESSENTIAL KNOWLEDGE |
| 5.7.A.1 A reaction mechanism consists of a series of elementary reactions, or steps, that occur in sequence. The components may include reactants, intermediates, products, and catalysts. |
| 5.7.A.2 The elementary steps when combined should align with the overall balanced equation of a chemical reaction. |
| 5.7.A.3 A reaction intermediate is produced by some elementary steps and consumed by others, such that it is present only while a reaction is occurring. |
| 5.7.A.4 Experimental detection of a reaction intermediate is a common way to build evidence in support of one reaction mechanism over an alternative mechanism. |
| Exclusion Statement: Collection of data pertaining to detection of a reaction intermediate will not be assessed on the AP Exam. |
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| LEARNING OBJECTIVE |
| 5.8.A Identify the rate law for a reaction from a mechanism in which the first step is rate limiting. |
| ESSENTIAL KNOWLEDGE |
| 5.8.A.1 For reaction mechanisms in which each elementary step is irreversible, or in which the first step is rate limiting, the rate law of the reaction is set by the molecularity of the slowest elementary step (i.e., the rate-limiting step). |
| Exclusion Statement: Collection of data pertaining to detection of a reaction intermediate will not be assessed on the AP Exam. |
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| LEARNING OBJECTIVE |
| 5.9.A Identify the rate law for a reaction from a mechanism in which the first step is not rate limiting. |
| ESSENTIAL KNOWLEDGE |
| 5.9.A.1 If the first elementary reaction is not rate limiting, approximations (such as pre-equilibrium) must be made to determine a rate law expression. |
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| LEARNING OBJECTIVE |
| 5.10.A Represent the activation energy and overall energy change in a multistep reaction with a reaction energy profile. |
| ESSENTIAL KNOWLEDGE |
| 5.10.A.1 Knowledge of the energetics of each elementary reaction in a mechanism allows for the construction of an energy profile for a multistep reaction. |
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| LEARNING OBJECTIVE |
| 5.11.A Explain the relationship between the effect of a catalyst on a reaction and changes in the reaction mechanism. |
| ESSENTIAL KNOWLEDGE |
| 5.11.A.1 In order for a catalyst to increase the rate of a reaction, the addition of the catalyst must increase the number of effective collisions and/or provide a reaction path with a lower activation energy relative to the original reaction coordinate. |
| 5.11.A.2 In a reaction mechanism containing a catalyst, the net concentration of the catalyst is constant. However, the catalyst will frequently be consumed in the rate-determining step of the reaction, only to be regenerated in a subsequent step in the mechanism. |
| 5.11.A.3 Some catalysts accelerate a reaction by binding to the reactant(s). The reactants are either oriented more favorably or react with lower activation energy. There is often a new reaction intermediate in which the catalyst is bound to the reactant(s). Many enzymes function in this manner. |
| 5.11.A.4 Some catalysts involve covalent bonding between the catalyst and the reactant(s). An example is acid-base catalysis, in which a reactant or intermediate either gains or loses a proton. This introduces a new reaction intermediate and new elementary reactions involving that intermediate. |
| 5.11.A.5 In surface catalysis, a reactant or intermediate binds to, or forms a covalent bond with, the surface. This introduces elementary reactions involving these new bound reaction intermediate(s). |
UNIT 6 Thermochemistry
Guiding question |
What happens when protons are transferred? |
Learning outcomes
After studying this topic you should be able to:
Understand | Apply your knowledge to |
pH = − log10[H+]; [H+] = 10−pH.
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AHL | AHL |
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| LEARNING OBJECTIVE |
| 6.2.A Represent a chemical or physical transformation with an energy diagram. |
| ESSENTIAL KNOWLEDGE |
| 6.2.A.1 A physical or chemical process can be described with an energy diagram that shows the endothermic or exothermic nature of that process. |
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| LEARNING OBJECTIVE |
| 6.3.A Explain the relationship between the transfer of thermal energy and molecular collisions. |
| ESSENTIAL KNOWLEDGE |
| 6.3.A.1 The particles in a warmer body have a greater average kinetic energy than those in a cooler body. |
| 6.3.A.2 Collisions between particles in thermal contact can result in the transfer of energy. This process is called “heat transfer,” “heat exchange,” or “transfer of energy as heat.” |
| 6.3.A.3 Eventually, thermal equilibrium is reached as the particles continue to collide. At thermal equilibrium, the average kinetic energy of both bodies is the same, and hence, their temperatures are the same. |
| Required Course Content |
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| LEARNING OBJECTIVE |
| 6.4.A Calculate the heat q absorbed or released by a system undergoing heating/cooling based on the amount of the substance, the heat capacity, and the change in temperature. |
| ESSENTIAL KNOWLEDGE |
| 6.4.A.1 The heating of a cool body by a warmer body is an important form of energy transfer between two systems. The amount of heat transferred between two bodies may be quantified by the heat transfer equation: |
| EQN: q = mcΔT. |
| Calorimetry experiments are used to measure the transfer of heat. |
| 6.4.A.2 The first law of thermodynamics states that energy is conserved in chemical and physical processes. |
| 6.4.A.3 The transfer of a given amount of thermal energy will not produce the same temperature change in equal masses of matter with differing specific heat capacities. |
| 6.4.A.4 Heating a system increases the energy of the system, while cooling a system decreases the energy of the system. |
| 6.4.A.5 The specific heat capacity of a substance and the molar heat capacity are both used in energy calculations. |
| 6.4.A.6 Chemical systems change their energy through three main processes: heating/cooling, phase transitions, and chemical reactions. |
| 6.4.A.7 In calorimetry experiments involving dissolution, temperature changes of the mixture within the calorimeter can be used to determine the direction of energy flow. If the temperature of the mixture increases, thermal energy is released by the dissolution process (exothermic). If the temperature of the mixture decreases, thermal energy is absorbed by the dissolution process (endothermic). |
| Required Course Content |
|---|
| LEARNING OBJECTIVE |
| 6.5.A Explain changes in the heat q absorbed or released by a system undergoing a phase transition based on the amount of the substance in moles and the molar enthalpy of the phase transition. |
ESSENTIAL KNOWLEDGE 6.5.A.1 Energy must be transferred to a system to cause a substance to melt (or boil). The energy of the system therefore increases as the system undergoes a solid-to-liquid (or liquid-to-gas) phase transition. Likewise, a system releases energy when it freezes (or condenses). The energy of the system decreases as the system undergoes a liquid-to-solid (or gas-to-liquid) phase transition. The temperature of a pure substance remains constant during a phase change. 6.5.A.2 The energy absorbed during a phase change is equal to the energy released during a complementary phase change in the opposite direction. For example, the molar enthalpy of condensation of a substance is equal to the negative of its molar enthalpy of vaporization. Similarly, the molar enthalpy of fusion can be used to calculate the energy absorbed when melting a substance and the energy released when freezing a substance. |
| Required Course Content |
|---|
| LEARNING OBJECTIVE |
| 6.6.A Calculate the heat q absorbed or released by a system undergoing a chemical reaction in relationship to the amount of the reacting substance in moles and the molar enthalpy of reaction. |
| ESSENTIAL KNOWLEDGE |
6.6.A.1 The enthalpy change of a reaction gives the amount of heat energy released (for negative values) or absorbed (for positive values) by a chemical reaction at constant pressure. 6.6.A.2 When the products of a reaction are at a different temperature than their surroundings, they exchange energy with the surroundings to reach thermal equilibrium. Thermal energy is transferred to the surroundings as the reactants convert to products in an exothermic reaction. Thermal energy is transferred from the surroundings as the reactants convert to products in an endothermic reaction. 6.6.A.3 The chemical potential energy of the products of a reaction is different from that of the reactants because of the breaking and forming of bonds. The energy difference results in a change in the kinetic energy of the particles, which manifests as a temperature change. |
| Exclusion Statement: The technical distinctions between enthalpy and internal energy will not be assessed on the AP Exam. Most reactions studied at the AP level are carried out at constant pressure, where the enthalpy change of the process is equal to the heat (and by extension, the energy) of reaction. |
| Required Course Content |
|---|
| LEARNING OBJECTIVE |
| 6.7.A Calculate the enthalpy change of a reaction based on the average bond energies of bonds broken and formed in the reaction. |
| ESSENTIAL KNOWLEDGE |
| 6.7.A.1 During a chemical reaction, bonds are broken and/or formed, and these events change the potential energy of the system. |
| 6.7.A.2 The average energy required to break all of the bonds in the reactant molecules can be estimated by adding up the average bond energies of all the bonds in the reactant molecules. Likewise, the average energy released in forming the bonds in the product molecules can be estimated. If the energy released is greater than the energy required, the reaction is exothermic. If the energy required is greater than the energy released, the reaction is endothermic. |
| Required Course Content |
|---|
| LEARNING OBJECTIVE |
| 6.8.A Calculate the enthalpy change for a chemical or physical process based on the standard enthalpies of formation. |
| ESSENTIAL KNOWLEDGE |
| 6.8.A.1 Tables of standard enthalpies of formation can be used to calculate the standard enthalpies of reactions. |
| EQN: ΔH°reaction = ΣΔHf°products − ΣΔHf°reactants |
| Required Course Content |
|---|
| LEARNING OBJECTIVE |
| 6.9.A Represent a chemical or physical process as a sequence of steps. |
| 6.9.B Explain the relationship between the enthalpy of a chemical or physical process and the sum of the enthalpies of the individual steps. |
| ESSENTIAL KNOWLEDGE |
6.9.A.1 Many processes can be broken down into a series of steps. Each step in the series has its own energy change. |
6.9.B.1 Because total energy is conserved (first law of thermodynamics), and each individual reaction in a sequence transfers thermal energy to or from the surroundings, the net thermal energy transferred in the sequence will be equal to the sum of the thermal energy transfers in each of the steps. These thermal energy transfers are the result of potential energy changes among the species in the reaction sequence; thus, at constant pressure, the enthalpy change of the overall process is equal to the sum of the enthalpy changes of the individual steps. |
6.9.B.2 The following are essential principles of Hess’s law: i. When a reaction is reversed, the enthalpy change stays constant in magnitude but becomes reversed in mathematical sign. |
| ii. When a reaction is multiplied by a factor c, the enthalpy change is multiplied by the same factor c. |
| iii. When two (or more) reactions are added to obtain an overall reaction, the individual enthalpy changes of each reaction are added to obtain the net enthalpy change of the overall reaction. |
| Exclusion Statement: The concept of state functions will not be assessed on the AP Exam. |
UNIT 7 Equilibrium
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